https://www.hackerearth.com/april-circuits/algorithm/circ-bear-and-vectors/ Two vectors v1( a1, b1 ), v2( a2, b2 ) are perpendicular to each other iff ( v1 dot v2 ) = a1 * a2 + b1 * b2 = 0. And since ( ka, kb ) = k( a, b ) is parallel to (…

https://www.hackerearth.com/april-circuits/approximate/2b-bear-and-walk-1/ It is not difficult to come up to the maze solving left / right hand rule. www.youtube.com Since the path is connected, it will work. However, there are several dif…

https://www.hackerearth.com/april-circuits/algorithm/2a-bear-and-all-permutations-1/ We can simply simulate for each answer since n is only up to 12. However, it still takes a lot of time, and the number is extremely large, we will have to…

https://www.hackerearth.com/april-circuits/algorithm/circ-bear-and-leaderboard-1/ For clarity, everything here concerning to index will be 0 based. For example rank of some participant will be equal to the number of participants having sco…

https://www.hackerearth.com/april-circuits/algorithm/circ-bear-and-vowels-2/ Simply simulate as the description provides. #include <bits/stdc++.h> using namespace std; const int MAXS = 50 + 2; const string vowel = "aeiouy"; string s; void solve(){ int vo</bits/stdc++.h>…